0=12x^2-74x+104

Solution for 0=12x^2-74x+104 equation:

0=12x^2-74x+104

We move all terms to the left:

0-(12x^2-74x+104)=0

We add all the numbers together, and all the variables

-(12x^2-74x+104)=0

We get rid of parentheses

-12x^2+74x-104=0

a = -12; b = 74; c = -104;
Δ = b2-4ac
Δ = 742-4·(-12)·(-104)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-22}{2*-12}=\frac{-96}{-24}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+22}{2*-12}=\frac{-52}{-24}
=2+1/6
$